Question:
A person swims from a depth of 0.5m to 1.7m below the surface of the sea. Density Sea Water = 1030 kg/m^3. g=Gravitational Field Strength = 9.8 N/kg. Calculate the change in pressure on the swimmer and give the unit.
Methods:
Use equation: Pressure = density x depth in the fluid x gravitational field strength. We know the in increase in pressure will be the difference between the Final Pressure (at 1.7m) and the Initial Pressure (at 0.5m).
Initial Pressure = 1030 x 0.5 x 9.8 = 5047.0 N/m2.
Final Pressure = 1030 x 1.7 x 9.8 = 17159.8 N/m2.
Increase in Pressure = Final Pressure – Initial Pressure = 17159.8 – 5047.0 = 12112.8 N/m2.
N/m2 is also known as Pascals (Pa).
If you are unsure about the units of pressure, use the units of the other variables in the equation to work out the units.
Answer:
Use equation: Pressure = density x depth in the fluid x gravitational field strength. We know the in increase in pressure will be the difference between the Final Pressure (at 1.7m) and the Initial Pressure (at 0.5m). Initial Pressure = 1030 x 0.5 x 9.8 = 5047.0 N/m2. Final Pressure = 1030 x 1.7 x 9.8 = 17159.8 N/m2. Increase in Pressure = Final Pressure – Initial Pressure = 17159.8 – 5047.0 = 12112.8 N/m2. N/m2 is also known as Pascals (Pa). If you are unsure about the units of pressure, use the units of the other variables in the equation to work out the units.
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