Question:
Simplify and then solve by factorisation 3x(x+2)-7=2, to find x.
Methods:
3x(x+2)-7=2
3x^2+6x-7=2
3x^2+6x-9=0
3(x^2+2x-3) = 0
[Divide by 3]
(x^2+2x-3) =0
(x+3) (x-1) =0
Answer:
x = -3 x = 1
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